Friday, June 7, 2013

Leap year program

Question: We have to ask user to enter year he/she wants, and give output whether its leap year or not?

Answer: Copy the below code and paste it into "your.php" file. After done this you will just need to run "your.php" file in browser and you will get the output successfully.

<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
        <title>leap year</title>
    </head>

    <body>
        <h1><center>leap year</center></h1>

        <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
            Enter the year in four digit:
            <input type="text" name="year" />
            <input type="submit" name="submit" value="OK" />
        </form>
        <?php
            if (isset($_POST['submit'])) {
                $yr = $_POST['year'];
                if ($yr % 4 == 0) {
                    if ($yr % 100 == 0) {
                        if ($yr % 400 == 0) {
                            echo $yr . " is leap year";
                        }
                        else
                            echo $yr . " is not leap year";
                    }
                    else
                        echo $yr . " is leap year";
                }
                else
                    echo $yr . " is not leap year";
            }
        ?>
    </body>
</html>

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